2 Fold Serial Dilution

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i had 10^8/ml and make a two-fold serial dilution of the culture so i had x2, x4, x6, x8, x16 and x32 dilution. how do i calculate the concentration of each dilution? please help moi.
thankyou :)
  1. 2 Fold Serial Dilution Illustration
  2. 2 Fold Dilution Series

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Serial two-fold and ten-fold dilutions are commonly used to titer antibodies or prepare diluted analytes (for a standard curve for example). Serial dilutions are also commonly used to avoid having to pipette very small volumes (1-10 µl) to make a dilution of a solution. The resulting mixture is diluted two-fold. B) Serial dilution for 2 ml NB and 8 ml of broth culture. Using a micropipette, dispense an 8ml broth culture into four test-tubes. Using a micropipette, dispense 2 ml NB in the test-tubes. Use the micropipette for the mixing of the dispensed contents by drawing and expelling them.

  • A two-fold dilution reduces the concentration of a solution by a factor of two that is reduces the original concentration by one half. A series of two-fold dilutions is described as two-fold serial dilutions. In this manual, two-fold serial dilutions are carried out in small volumes in microwell plates. Click to see full answer.
  • For example, 2 fold dilution equals to 1:2 dilution. Since you mentioned serial dilution, you do this by first mixing an equal volume of bacteria and water (whatever used for dilution), and then. A serial dilution is the stepwise dilution of a substance in solution.

That is easy, you dilute it 2 times with every dilution, except for the x6 dilution, which does not belong in this series.
So first you had 1 x 10^8 per ml
in the 2x dilution, you have 0.5 x 10^8 per ml = 5 x 10^7 per ml
in the 4x dilution, you have 0.25 x 10^8 per ml = 2.5 x 10^7 per ml
in the x8 dilution, you have 0.125 x 10^8 per ml = 1.25 x 10^7 per ml
and so on..

2 Fold Serial Dilution Illustration

How do we dilute a bacterial culture 50-fold, 100-fold, and 200-fold?

1 Answer

You could do the dilutions in one step, or you might have to do serial dilutions.

Explanation:

There is a limit to how much you can dilute a sample in one step.

You probably wouldn't want to dilute by more than a factor of 100 in a single step, because that would give you a large volume of dilute solution.

Rather, you would use the serial dilution technique.

Remember the formula for dilution factor (#'DF'#):

#'DF' = V_f/V_i#, where

#V_i = 'aliquot volume'# and

#V_f = 'final volume' = 'aliquot volume + diluent volume'#

(a)#'DF' = 50#

Here we can do a single dilution.

We can add 0.2 mL of sample to 9.8 mL of diluent (normal saline? cells will burst in distilled water because of osmotic pressure).

#V_f = '0.2 mL + 9.8 mL' = '10.0 mL'#

#'DF' = V_f/V_i = (10.0 cancel('mL'))/(0.2 cancel('mL')) = 50#

(b)#'DF' = 100#

Here, too, we can do a single dilution.

This time we add 0.1 mL of sample to 9.9 mL of saline.

#V_f = '0.1 mL + 9.9 mL' = '10.0 mL'#

#'DF' = V_f/V_i = (10.0 cancel('mL'))/(0.1 cancel('mL')) = 100#

(c)#'DF' = 200#

Here you might want to do a serial dilution.

The formula for serial dilutions is

#'DF' = 'DF'_1 × 'DF'_2 × 'DF'_3 ×…#

How about a 1:100 dilution followed by a 1:2 dilution?

(1) Add 0.1 mL of sample to 9.9 mL of diluent. #'DF'_1 = 100#. Swargroove vst crack download. Call this 'Solution 1'.

(2) Add 5 mL of Solution 1 to 5 mL of saline. Call this 'Solution 2'.

#V_i = '5 mL'#

#V_f = '5 mL + 5 mL' = '10 mL'#

#'DF'_2 = V_f/V_i = (10 cancel('mL'))/(5 cancel('mL')) = 2#

2 Fold Dilution Series

#'DF' = 'DF'_1 × 'DF'_2 = 100 × 2 = 200#

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